CBSEGrade 12PhysicsMoving Charges and Magnetism

Magnetic Field around a Current Loop?

A circular coil of wire of 50 turns and a radius of 20 cm carries a current of 2 A. Calculate and describe the direction and magnitude of the magnetic field at the center of the coil. Consider the effect of doubling the current and halving the number of turns on the magnetic field strength.

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📌 CONCEPT: The magnetic field around a current loop is a region around the loop where the magnetic force can be detected.

📐 RULE / FORMULA: The magnetic field strength (B) at the center of a circular loop is given by the formula B = μ₀ × (N × I) / r, where μ₀ is the magnetic constant, N is the number of turns, I is the current, and r is the radius of the loop.

💡 WORKED EXAMPLE: A circular coil of 100 turns and a radius of 25 cm carries a current of 3 A. Using the formula, we find B = (4π × 10^(-7)) × (100 × 3) / 0.25 = 1.2 × 10^(-3) T.

⚠️ COMMON MISTAKE: Students often forget to include the number of turns (N) in the formula, which can lead to incorrect answers.

04 Aug 26

📖 Chapter Resource

Moving Charges and Magnetism

Physics · Grade 12

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