CBSEGrade 12PhysicsMoving Charges and Magnetism

Magnetic Field of a Solenoid?

A current of 2 A flows through a solenoid of 100 turns and length 0.1 m. If the magnetic field inside the solenoid is 100 μT, what is the magnetic moment of the solenoid? Assume the current is switched off and then the solenoid is used as a magnet. How would the magnetic moment change if the number of turns is doubled and the length is halved?

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📌 CONCEPT: The magnetic moment of a solenoid is a measure of its ability to produce a magnetic field when used as a magnet, and it depends on the number of turns, the length of the solenoid, and the current flowing through it.

📐 RULE / FORMULA: The magnetic field (B) inside a solenoid is given by the formula B = μ₀nI, where μ₀ is the magnetic constant (4π × 10⁻⁷ Tm/A), n is the number of turns per unit length, and I is the current flowing through the solenoid. The magnetic moment (M) of a solenoid can be calculated using the formula M = nIA.

💡 WORKED EXAMPLE: Given a solenoid of 100 turns and length 0.1 m with a current of 2 A, and a magnetic field of 100 μT, we can calculate the magnetic moment as follows: M = nIA = (100 / 0.1 A/m) × 2 A = 2000 A/m². The magnetic moment is then M = B / (μ₀n) = (100 × 10⁻⁶ T) / (4π × 10⁻⁷ Tm/A × 100 A/m) = 2000 A/m².

⚠️ COMMON MISTAKE: Students often forget to convert the magnetic field from microtesla (μT) to tesla (T) and also misinterpret the units of the magnetic constant (μ₀).

17 Oct 26