Magnetic Field and Electric Current Interaction?
A straight wire of length 2 meters carries a current of 5 A. It is placed perpendicular to a uniform magnetic field of strength 0.3 T. The wire is then bent into a semicircle of radius 0.5 meters. How does the magnetic field strength required to produce a force of 50 mN on the wire affect the length of the wire?
1 Answer
📌 CONCEPT: The magnetic field strength required to produce a force on a current-carrying wire is determined by the interaction between the magnetic field and the electric current flowing through the wire.
📐 RULE / FORMULA: The force experienced by a current-carrying wire in a magnetic field is given by the formula F = BIL sin θ, where F is the force, B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.
💡 WORKED EXAMPLE: Suppose we have a wire of length 2 meters carrying a current of 5 A. If the wire is placed perpendicular to a uniform magnetic field of strength 0.3 T, and we want to produce a force of 50 mN on the wire. Using the formula F = BIL sin θ, we can calculate the magnetic field strength required. First, we calculate the force using the given values, then we rearrange the formula to solve for B.
⚠️ COMMON MISTAKE: Students often forget to consider the angle between the wire and the magnetic field, which is assumed to be 90 degrees in this problem. They should also ensure that the units of the force and the magnetic field strength are consistent, typically in Newtons and Tesla respectively.
13 Oct 26
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