CBSEGrade 12PhysicsElectrostatic Potential and Capacitance

Parallel Plate Capacitor in Space?

Two parallel plate capacitors of capacitance 100 μF each are connected in series. If one capacitor is placed on the surface of the Earth and the other is taken to a height of 2 R (where R is the radius of the Earth), how will the equivalent capacitance of the circuit change, and why?

💬 1 answers0 votes👁 28 views02 August 2026

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📌 CONCEPT: The capacitance of a parallel plate capacitor is affected by the distance between its plates, and in this case, the change in distance is due to the difference in height between the two capacitors.

📐 RULE / FORMULA: When capacitors are connected in series, the equivalent capacitance (Ceq) is given by 1/Ceq = 1/C1 + 1/C2, and the capacitance of a parallel plate capacitor (C) is given by C = ε0 * A / d, where ε0 is the permittivity of free space, A is the plate area, and d is the distance between the plates.

💡 WORKED EXAMPLE: Let's consider two parallel plate capacitors of capacitance 100 μF each, one on the Earth's surface and the other at a height of 2R. The capacitance of the second capacitor will increase by a factor of (R / (R + 2R)) = 1/3 due to the increased distance between its plates. Since they are connected in series, the equivalent capacitance will decrease, and 1/Ceq = 1/100 + 1/(100/3), resulting in a decrease in Ceq.

⚠️ COMMON MISTAKE: Students often forget to consider the effect of the change in distance on the capacitance of the second capacitor, leading to an incorrect calculation of the equivalent capacitance.

02 Aug 26