CBSEGrade 12PhysicsElectrostatic Potential and Capacitance

Cascading Capacitors: A Charging Conundrum?

Three capacitors of capacitances 2 μF, 3 μF, and 4 μF are connected in cascade. If a potential difference of 12 V is applied across the combination, determine the potential difference across each capacitor and the total charge stored in the circuit. Assume the capacitors are initially uncharged and the charging process is ideal.

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📌 CONCEPT: In a cascading capacitor circuit, each capacitor stores charge from the previous one, with the potential difference across each capacitor determined by its capacitance and the charge it stores.

📐 RULE / FORMULA: The charge stored in each capacitor is the same (Q), and the potential difference across each capacitor is inversely proportional to its capacitance, given by the formula V = Q/C, where V is the potential difference, Q is the charge, and C is the capacitance.

💡 WORKED EXAMPLE: If three capacitors of capacitances 2 μF, 3 μF, and 4 μF are connected in cascade and a potential difference of 12 V is applied across the combination, let's find the potential difference across each capacitor and the total charge stored. Using the formula V = Q/C, we can find the charge Q = 12 V * (2 μF + 3 μF + 4 μF) = 54 μC. Then, V1 = 54 μC / 2 μF = 27 V, V2 = 54 μC / 3 μF = 18 V, and V3 = 54 μC / 4 μF = 13.5 V.

⚠️ COMMON MISTAKE: Students often forget that the charge stored in each capacitor is the same, leading to incorrect calculations of potential differences.

04 Oct 26