Magnetic Field Around a Current-Carrying Wire?
Consider a long straight copper wire carrying a current of 2 A from east to west, placed inside a copper ring. If the ring is connected to a battery and the current through the ring increases by 4 A, how will the magnetic field around the wire change?
1 Answer
📌 CONCEPT: The magnetic field around a current-carrying wire is a result of the interaction between the wire's current and the magnetic field generated by it, which depends on the direction of the current and the distance from the wire.
📐 RULE / FORMULA: According to Ampere's law, the magnetic field (B) around a long straight current-carrying wire is directly proportional to the current (I) flowing through it and inversely proportional to the distance (r) from the wire, given by the formula: B = μ₀ I / (2πr).
💡 WORKED EXAMPLE: Suppose we have a long straight copper wire carrying a current of 2 A and placed inside a copper ring. If the current through the ring increases by 4 A, the magnetic field around the wire will also increase. Let's assume the initial magnetic field is B₁ and the final magnetic field is B₂. Using Ampere's law, we can calculate the initial and final magnetic fields as B₁ = μ₀ (2 A) / (2πr) and B₂ = μ₀ (2 A + 4 A) / (2πr), respectively. The ratio of the final magnetic field to the initial magnetic field is B₂ / B₁ = (2 A + 4 A) / (2 A).
⚠️ COMMON MISTAKE: Students often forget to consider the direction of the current and the magnetic field when applying Ampere's law, leading to incorrect calculations of the magnetic field strength.
28 Jul 26
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