CBSEGrade 12PhysicsElectric Charges and Fields

Effect of Shielding on Electric Field?

Consider a point charge of +3 μC placed at a distance of 2 meters from a large conducting spherical shell of radius 1 meter. If a small hole is made in the shell at the point closest to the charge, how does the electric field strength at the surface of the shell change compared to when the shell is intact?

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📌 CONCEPT: Shielding of electric field using a conducting spherical shell involves the redistribution of charges on the shell's surface to neutralize the external electric field, except at the point closest to the charge if a small hole is made.

📐 RULE / FORMULA: According to Gauss's Law, the electric flux through a closed surface is proportional to the charge enclosed by the surface. If the shell is intact, the charge on the shell's surface will be equal and opposite to the external charge, resulting in zero electric field inside and outside the shell.

💡 WORKED EXAMPLE: Consider a point charge of +3 μC placed at a distance of 2 meters from a large conducting spherical shell of radius 1 meter. If a small hole is made in the shell at the point closest to the charge, the electric field strength at the surface of the shell will remain unchanged compared to when the shell is intact. This is because the hole does not affect the redistribution of charges on the shell's surface.

⚠️ COMMON MISTAKE: Students often incorrectly assume that the electric field will change significantly due to the presence of a small hole in the shell, when in fact the hole does not affect the redistribution of charges and thus the electric field strength remains the same.

27 Aug 26