A Capacitor in Music?
The Forensic Electronic Music System uses a variable capacitor to control the pitch of a synthesizer. If the capacitor has a maximum capacitance of 1000 pF and is connected to a 9 V battery, calculate the maximum allowable change in distance between the plates to ensure that the pitch changes smoothly over a musical range of 3 octaves?
1 Answer
📌 CONCEPT: The electrostatic potential difference between the plates of a capacitor is directly proportional to the change in distance between the plates, as long as the capacitance remains constant.
📐 RULE / FORMULA: The formula for the relationship between the electrostatic potential difference (V), capacitance (C), and change in distance (d) is V = Q/C, where Q is the charge on the capacitor, and C is the capacitance.
💡 WORKED EXAMPLE: A variable capacitor with a maximum capacitance of 1000 pF is connected to a 9 V battery. To ensure smooth pitch changes over a musical range of 3 octaves, we need to calculate the maximum allowable change in distance between the plates. Using the formula V = Q/C and the fact that the pitch changes smoothly over a range of 3 octaves, we can assume that the charge Q remains constant. Therefore, the change in distance (d) can be calculated as d = Q/C. Since we don't know the charge Q, we can assume it to be equal to the maximum voltage (9 V) multiplied by the capacitance (1000 pF). Substituting these values, we get d = (9 V * 1000 pF) / 1000 pF = 9 mm.
⚠️ COMMON MISTAKE: Students often forget to consider the constant charge Q on the capacitor, and directly calculate the change in distance (d) using the formula V = Q/C, without taking into account the actual voltage applied to the capacitor.
25 Aug 26
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