CBSEGrade 11PhysicsChapter 6: Systems of Particles and Rotational Motion

Torque on a Couple of Pulleys?

Ashish is using a system of two pulleys to lift a load of 100 N. The first pulley is connected to a fixed point and the second pulley is connected to a horizontal beam, which exerts a force of 20 N on the first pulley. If the radius of the pulleys is 5 cm, what is the angular acceleration of the load when it is lifted at a constant rate of 1 m/s^2?

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📌 CONCEPT: A couple of pulleys is a system of two pulleys that allows a force to be applied at a distance from the load, resulting in a torque that causes the load to rotate.

📐 RULE / FORMULA: The torque on the load is given by τ = r × F, where τ is the torque, r is the radius of the pulley, and F is the force applied to the pulley.

💡 WORKED EXAMPLE: Given that the force applied to the first pulley is 20 N and the radius of the pulley is 5 cm, we can calculate the torque on the load. Using the formula τ = r × F, we get τ = 0.05 m × 20 N = 1 Nm. Since the load is lifted at a constant rate, the torque is also constant, and we can use the formula τ = I × α to find the angular acceleration α. However, we are not given the moment of inertia I, so we need to use the fact that the load is lifted at a constant rate of 1 m/s^2 to find the angular acceleration.

⚠️ COMMON MISTAKE: Students may forget to consider the radius of the pulley when calculating the torque, or they may assume that the torque is zero since the force is applied horizontally.

07 Jun 26

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Chapter 6: Systems of Particles and Rotational Motion

Physics · Grade 11

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