CBSEGrade 11PhysicsChapter 6: Systems of Particles and Rotational Motion

Tension in a Rotating System?

A boy is sitting on a see-saw with his friend, where they are connected by a rope over a pulley. The boy's mass is 50 kg and his friend's mass is 30 kg. If the boy starts rotating the see-saw with an angular velocity of 2 rad/s, how does the tension in the rope affect the boy's acceleration?

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📌 CONCEPT: In a rotating system, the tension in the rope connected to the rotating part affects the acceleration of the boy by providing a net force due to the difference in the weights of the boy and his friend.

📐 RULE / FORMULA: The tension in the rope is given by T = (m2 - m1)g, where m1 and m2 are the masses of the boy and his friend, and g is the acceleration due to gravity.

💡 WORKED EXAMPLE: Suppose the boy's mass is 50 kg and his friend's mass is 30 kg. If the boy starts rotating the see-saw with an angular velocity of 2 rad/s, we can calculate the tension in the rope using the formula T = (50 kg - 30 kg) × 9.8 m/s² = 158 N. The acceleration of the boy can be found using F = ma, where F is the net force due to the tension, a is the acceleration, and m is the mass of the boy.

⚠️ COMMON MISTAKE: Students often forget to consider the difference in the weights of the boy and his friend, leading to an incorrect calculation of the tension in the rope and the boy's acceleration.

27 Sept 26