Tipping Point of Gyroscope?
A gyroscope is mounted on a frictionless rotating turntable. If the gyroscope's angular velocity is 2 rad/s about its axis of symmetry, and it experiences a torque of 0.5 Nm perpendicular to its axis, determine the minimum angular velocity the turntable must have to prevent the gyroscope from tipping.
1 Answer
📌 CONCEPT: The tipping point of a gyroscope is the minimum angular velocity required for its axis of symmetry to remain stable and prevent tipping, even when subjected to a torque perpendicular to its axis.
📐 RULE / FORMULA: The condition for the gyroscope to remain stable is given by the equation ωt ≥ τ / I, where ωt is the minimum angular velocity of the turntable, τ is the torque applied to the gyroscope, and I is the moment of inertia of the gyroscope.
💡 WORKED EXAMPLE: Given that the gyroscope's angular velocity is 2 rad/s and it experiences a torque of 0.5 Nm, the minimum angular velocity the turntable must have to prevent the gyroscope from tipping can be calculated using the equation ωt = τ / I. Assuming the moment of inertia of the gyroscope is 0.1 kg m², we can calculate ωt as ωt = 0.5 / 0.1 = 5 rad/s.
⚠️ COMMON MISTAKE: Students often forget to consider the moment of inertia of the gyroscope, which is essential in determining the minimum angular velocity required to prevent tipping.
05 Aug 26
🔗 More from Chapter 6: Systems of Particles and Rotational Motion
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