CBSEGrade 11PhysicsChapter 6: Systems of Particles and Rotational Motion

Roller Coaster Physics?

A roller coaster car of mass 2000 kg moves in a vertical circle of radius 20 m with a speed of 12 m/s. If the track is banked at an angle of 30°, determine the normal force acting on the car at the topmost point of the circle.

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📌 CONCEPT: When a roller coaster car moves in a banked circular track, the normal force acting on it is determined by the combination of its velocity, the angle of banking, and the radius of the circular path.

📐 RULE / FORMULA: The normal force (N) can be calculated using the formula N = mg / cos(θ) + (mv^2) / (r * cos(θ)), where m is the mass of the car, g is the acceleration due to gravity, v is the velocity of the car, r is the radius of the circle, and θ is the angle of banking.

💡 WORKED EXAMPLE: Given that the roller coaster car has a mass of 2000 kg, is moving at a speed of 12 m/s, and the track is banked at an angle of 30° with a radius of 20 m, we can calculate the normal force at the topmost point of the circle using the formula. First, we find the force due to gravity: N = mg / cos(30°) = (2000 * 9.8) / (1 / sqrt(3)) = 10480.5 N. Then, we calculate the force due to the circular motion: N = (2000 * (12)^2) / (20 * sqrt(3)) = 1182.8 N. Finally, we add both forces: N = 10480.5 + 1182.8 = 11663.3 N.

⚠️ COMMON MISTAKE: Students often forget to account for the angle of banking in the calculation of the normal force, leading to an incorrect result.

01 Jul 26

📖 Chapter Resource

Chapter 6: Systems of Particles and Rotational Motion

Physics · Grade 11

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