Projectile Motion Puzzle?
A particle is projected from the ground with an initial velocity of 20 m/s at an angle of 60° above the horizontal. Assuming air resistance is negligible, would the range of the projectile be greater if it were projected from a height of 10 m above the ground or if it were projected from the ground with an initial velocity of 25 m/s at the same angle?
1 Answer
📌 CONCEPT: In projectile motion, the range is the maximum horizontal distance traveled by an object, and it depends on the initial velocity, angle of projection, and the acceleration due to gravity.
📐 RULE / FORMULA: The range (R) of a projectile can be calculated using the formula R = (u^2 * sin(2θ)) / g, where u is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity.
💡 WORKED EXAMPLE: If a particle is projected with an initial velocity of 20 m/s at an angle of 60° above the horizontal, its range can be calculated as R = ((20)^2 * sin(120°)) / 9.8. First, calculate sin(120°), which is approximately 0.866. Then, substitute the values in the formula to get R ≈ (400 * 0.866) / 9.8 ≈ 35.42 m.
⚠️ COMMON MISTAKE: Students often forget to consider the effect of air resistance in projectile motion, which is negligible in this scenario. However, they may also make errors in calculating the range by incorrectly applying the formula or neglecting to substitute the correct values for the variables.
07 Oct 26
🔗 More from Chapter 3: Motion in a Plane
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