CBSEGrade 11PhysicsChapter 3: Motion in a Plane

Projectile Motion Interference?

A particle is projected with an initial velocity of 20 m/s at an angle of elevation 'α' with the horizontal. Another particle is projected with the same initial velocity but at an angle 'β' from the horizontal. The two particles collide at a certain point in space. Explain the conditions under which 'α' and 'β' will be equal, and discuss the implications for the trajectory of the projectiles.

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📌 CONCEPT: For two particles to collide in projectile motion, their trajectories must intersect at a specific point in space, implying that their paths are constrained by the initial velocities and angles of projection.

📐 RULE / FORMULA: The condition for the particles to collide is given by the equation: tan(α) = (v0y / v0x) = (v0 sin(β)) / v0 cos(β), where v0x and v0y are the horizontal and vertical components of the initial velocity.

💡 WORKED EXAMPLE: Suppose a particle is projected at an angle α = 30° with an initial velocity of 20 m/s. Another particle is projected at an angle β = 60° with the same initial velocity. To find the condition for the two particles to collide, we can use the formula: tan(α) = (20 sin(60°)) / (20 cos(30°)), which simplifies to tan(30°) = √3, implying that α = 30° and β = 60° are the only angles for which the particles will collide.

⚠️ COMMON MISTAKE: Students often overlook the fact that the condition for collision requires the trajectories to intersect at a specific point in space, and may incorrectly assume that the particles will always collide if their initial velocities and angles are the same.

10 Oct 26