Roller Coaster's Sharp Turns?
A roller coaster's track is modelled by the function f(x) = 2x^3 - 5x^2 - 20x + 7, where x is the horizontal distance in meters and f(x) is the height of the roller coaster above the ground. At a particular point, the roller coaster takes a sharp turn at a height of 25 meters. If the roller coaster's speed is 5 m/s, will it be able to take the turn safely without losing control?
1 Answer
📌 CONCEPT: The roller coaster's ability to take the sharp turn safely without losing control can be determined by analyzing its continuity and differentiability at the point of the turn, as a change in the roller coaster's shape or direction can indicate a loss of control.
📐 RULE / FORMULA: For a function to be differentiable at a point, it must be continuous at that point. This is known as the 'Differentiation Rule' or 'Darboux's Theorem.'
💡 WORKED EXAMPLE: Given f(x) = 2x^3 - 5x^2 - 20x + 7, to determine if the roller coaster can take the turn at x = a, we first find the first derivative f'(x) and evaluate it at x = a. If f'(a) exists and is finite, the roller coaster is differentiable at that point, indicating it can take the turn safely.
⚠️ COMMON MISTAKE: Students often incorrectly assume that a function is differentiable at a point if its first derivative exists and is finite, without considering the continuity of the function. However, continuity is a necessary condition for differentiability.
16 Jul 26
🔗 More from Continuity and Differentiability
Practice this chapter
Get AI-generated board exam questions, track your mastery, and identify weak spots.
Start Free →