Modeling Population Growth?
The population of a certain insect is growing at a rate proportional to the number of insects present. If the population doubles in 10 years, and initially there were 500 insects, use the differential equation to find the population after 20 years, and discuss the implications of this growth.
1 Answer
📌 CONCEPT: The population growth of an insect can be modeled using the differential equation dP/dt = kP, where P is the population at time t and k is the growth rate constant.
📐 RULE / FORMULA: The differential equation dP/dt = kP can be solved using separation of variables, giving P(t) = P0 * e^(kt), where P0 is the initial population.
💡 WORKED EXAMPLE: Given that the population doubles in 10 years and initially there were 500 insects, we can find k as follows: Since P(10) = 2 * P0, we have 2 * 500 = 500 * e^(10k). Simplifying, we get e^(10k) = 2. Taking the natural logarithm of both sides, we get 10k = ln(2), so k = ln(2)/10. Now, to find the population after 20 years, we substitute t = 20 into the equation P(t) = P0 * e^(kt), giving P(20) = 500 * e^(20 * ln(2)/10) = 500 * e^(2 * ln(2)) = 500 * (e^ln(2))^2 = 500 * 2^2 = 2000.
⚠️ COMMON MISTAKE: Students often forget to take the natural logarithm of both sides when solving for k, leading to an incorrect value of k.
20 Jul 26
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