CBSEGrade 12PhysicsMoving Charges and Magnetism

Magnetic Field of a Current-Carrying Loop?

A circular loop of wire with a radius of 10 cm carries a current of 5 A. If the loop is placed in a uniform magnetic field of 0.5 T, what is the direction and magnitude of the magnetic field produced by the current-carrying loop at its center?

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📌 CONCEPT: The magnetic field produced by a current-carrying loop is a result of the interaction between the electric current and the magnetic field, leading to the generation of an additional magnetic field at its center. This phenomenon is known as the 'magnetic field of a current-carrying loop'. The direction of the additional magnetic field is such that it opposes the original magnetic field.

📐 RULE / FORMULA: To find the magnetic field produced by a current-carrying loop, we can use the formula B = (μ0 * I) / (2 * r), where B is the magnetic field, μ0 is the magnetic constant, I is the current, and r is the radius of the loop.

💡 WORKED EXAMPLE: Given a circular loop of wire with a radius of 10 cm (0.1 m) and a current of 5 A, we can calculate the magnetic field produced at its center. Using the formula B = (μ0 * I) / (2 * r), we can substitute the values to get B = (4π * 10^(-7) * 5) / (2 * 0.1) T.

⚠️ COMMON MISTAKE: Students often forget to consider the direction of the magnetic field produced by the current-carrying loop, which is perpendicular to the plane of the loop and directed according to the right-hand rule.

25 Aug 26