Kirchhoff's Loop Rule Conundrum?
In a circuit containing a 2 Ω resistor, a 3 V battery, and an unknown inductor, the total resistance is measured to be 5 Ω. Using only Kirchhoff's loop rule, derive an expression for the inductance of the inductor and discuss its implications on the circuit.
1 Answer
📌 CONCEPT: Kirchhoff's Loop Rule is a fundamental principle in circuit analysis that states the sum of changes in potential around any closed loop in a circuit is zero.
📐 RULE / FORMULA: According to Kirchhoff's Loop Rule, the sum of the potential differences across the components in a loop is zero, given by the equation: Σ(V) = 0, where V represents the potential difference across each component in the loop.
💡 WORKED EXAMPLE: In the given circuit with a 2 Ω resistor, a 3 V battery, and an unknown inductor, we can apply the loop rule as follows: (3 V) - (εL) - (iR)(2 Ω) = 0, where εL is the induced emf across the inductor, and i is the current in the circuit. To find the inductance, we need to first determine the current i, which can be calculated using Ohm's law: i = V/R = 3/5 A. Substituting this value, we get: (3 V) - (i)(5 Ω)(di/dt) = 0, which simplifies to L(di/dt) = 3 - 6i. Solving for L, we get: L = (3 - 6i)/di/dt.
⚠️ COMMON MISTAKE: Students often confuse the loop rule with Kirchhoff's Junction Rule and apply the wrong equation to the circuit, leading to incorrect results.
23 Oct 26
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