CBSEGrade 12MathematicsVector Algebra

Interpreting Velocity Vectors in Projectile Motion?

A particle is projected from ground level with an initial velocity of 25 m/s at an angle of 60° to the horizontal. Assuming the acceleration due to gravity is 9.8 m/s² downward, represent the velocity of the particle 2 seconds after projection in terms of its horizontal and vertical components, and analyze its effect on the trajectory of the particle.

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📌 CONCEPT: In projectile motion, the velocity vector of a particle can be represented as a sum of its horizontal and vertical components, each with a magnitude and direction, which together determine the trajectory of the particle.

📐 RULE / FORMULA: The horizontal component of the velocity vector remains constant, while the vertical component is affected by the acceleration due to gravity, and can be represented as v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is time.

💡 WORKED EXAMPLE: A particle is projected with an initial velocity of 25 m/s at an angle of 60° to the horizontal. 2 seconds after projection, the horizontal component of its velocity remains 25 m/s, while the vertical component is affected by the acceleration due to gravity, and can be calculated as v = 25 m/s - 9.8 m/s² × 2 s = -19.6 m/s.

⚠️ COMMON MISTAKE: Students often forget to account for the acceleration due to gravity when calculating the vertical component of the velocity vector, leading to an incorrect representation of the particle's trajectory.

30 Sept 26