Induced Voltage in Alternating Fields?
A conductor is placed in an alternating magnetic field of frequency 50 Hz. Explain, with suitable mathematical reasoning, how the induced voltage in the conductor changes with time, assuming the magnetic field's amplitude remains constant.
1 Answer
📌 CONCEPT: Electromagnetic induction refers to the phenomenon where a changing magnetic field induces an electric field in a conductor, resulting in the generation of an electromotive force (EMF) or voltage.
📐 RULE / FORMULA: The induced voltage (ε) in a conductor placed in a changing magnetic field can be calculated using Faraday's law of electromagnetic induction, which states that ε = -N(dΦ/dt), where N is the number of turns of the conductor and Φ is the magnetic flux through the conductor.
💡 WORKED EXAMPLE: Consider a conductor with 100 turns placed in an alternating magnetic field with a frequency of 50 Hz. The magnetic field's amplitude remains constant at 10 mT. Using Faraday's law, we can calculate the induced voltage as ε = -N(dΦ/dt). Assuming the magnetic flux Φ varies sinusoidally with time, we can write dΦ/dt = 2πfΦm, where f is the frequency and Φm is the maximum magnetic flux. Substituting the values, we get ε = -100(2π(50)(10 × 10^(-3)))sin(2πft).
⚠️ COMMON MISTAKE: Students often confuse the direction of the induced voltage with the direction of the changing magnetic field, forgetting that the induced voltage is a result of the rate of change of the magnetic field.
25 Oct 26
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