Evaluating Integral Limits?
Consider a curve where the distance from the x-axis is given by the function y = √(x^2 + 1). Evaluate the definite integral of this function from -1 to 1 and interpret the result geometrically.
1 Answer
📌 CONCEPT: The definite integral of a function f(x) from a to b represents the area under the curve of f(x) between the limits a and b.
📐 RULE / FORMULA: The definite integral can be evaluated using the Fundamental Theorem of Calculus (FTC), which states that ∫[a,b] f(x) dx = F(b) - F(a), where F(x) is the antiderivative of f(x).
💡 WORKED EXAMPLE: Consider the function y = √(x^2 + 1) and evaluate the definite integral from -1 to 1. First, we find the antiderivative of y = √(x^2 + 1), which is F(x) = (1/2)(x√(x^2 + 1) + ln|x + √(x^2 + 1)|). Then, we apply the FTC: ∫[-1,1] √(x^2 + 1) dx = F(1) - F(-1) = (1/2)((1√(1^2 + 1) + ln|1 + √(1^2 + 1)|) - ((-1)√((-1)^2 + 1) + ln|-1 + √((-1)^2 + 1)|)) = (1/2)(√2 + ln(√2 + 1) + √2 - ln(√2 - 1))
⚠️ COMMON MISTAKE: Students often forget to apply the absolute value to the natural logarithm in the antiderivative, which can lead to incorrect results.
10 Aug 26
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