Electric Field due to Spherical Shell?
A spherical shell of radius 10 cm has a total charge of 4 μC uniformly distributed over its surface. If a tiny test charge of -2 μC is placed at the centre of the shell, will it experience any net electric field and what would be its direction?
1 Answer
📌 CONCEPT: The electric field due to a spherical shell is zero at every point outside the shell, as per the properties of a spherical charge distribution.
📐 RULE / FORMULA: The electric field at the centre of a spherical shell is given by E = k * q / r^2, where q is the charge on the shell and r is the radius of the shell.
💡 WORKED EXAMPLE: For a spherical shell with radius 10 cm and charge 4 μC, the electric field at its centre would be E = (9 * 10^9 N m^2 C^-2) * (4 * 10^-6 C) / (0.1 m)^2, which simplifies to E = 0 N/C. This is because the test charge of -2 μC placed at the centre of the shell would experience no net electric field.
⚠️ COMMON MISTAKE: Students often fail to consider the properties of spherical charge distributions and incorrectly assume that the electric field at the centre of a spherical shell is non-zero.
05 Oct 26
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