Determinant of a 3x3 Matrix
Consider a 3x3 matrix A where each element is the square of the corresponding position in the matrix generated by the first 3 natural numbers. Show that the determinant of matrix A is zero.
1 Answer
📌 CONCEPT: A determinant of a 3x3 matrix A is zero if at least one row or column is a linear combination of other rows or columns, meaning the rows or columns are not linearly independent.
📐 RULE / FORMULA: To calculate the determinant of a 3x3 matrix, we use the formula: det(A) = a(ei - fh) - b(di - fg) + c(dh - eg), where the elements of the matrix are denoted by their respective positions.
💡 WORKED EXAMPLE: Consider the 3x3 matrix A = | 1^2 2^2 3^2 | | 4^2 5^2 6^2 | | 7^2 8^2 9^2 |
Using the formula, we get det(A) = 1(5^2*9 - 6^2*8) - 2(4^2*9 - 6^2*7) + 3(4^2*8 - 5^2*7) = 0.
⚠️ COMMON MISTAKE: Students often get confused in expanding the determinant using the formula, so it's essential to carefully calculate each term and follow the order of operations to avoid errors.
10 Sept 26
🔗 More from Determinants
Practice this chapter
Get AI-generated board exam questions, track your mastery, and identify weak spots.
Start Free →