CBSEGrade 11PhysicsChapter 5: Work, Energy and Power

Rider's Energy Conundrum?

A bicycle rider on a frictionless surface accelerates from rest for 5 seconds with a constant power of 50 W. Find the distance covered by the rider in the next 10 seconds if she continues to apply the same power but at a speed of 5 m/s.

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📌 CONCEPT: The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. This theorem helps us relate power to the distance traveled by an object. It assumes that the force applied is constant and in the direction of motion.

📐 RULE / FORMULA: The formula for work done (W) is given by W = F × s, where F is the force applied and s is the displacement in the direction of the force. Alternatively, we can use the equation W = (1/2) × m × v^2, where m is the mass and v is the final velocity of the object. Since power (P) is the rate at which work is done, we have P = W / t, where t is the time taken.

💡 WORKED EXAMPLE: A 50 W bicycle rider accelerates from rest for 5 seconds. We can find the work done in the first 5 seconds using the power and time formula: W = P × t = 50 W × 5 s = 250 J. Since the rider continues to apply the same power, the distance covered in the next 10 seconds can be calculated using the work-energy theorem: W = (1/2) × m × v^2. We know the work done in the first 5 seconds is 250 J, and the rider's speed is 5 m/s. We can find the distance covered in the next 10 seconds by equating the work done to the change in kinetic energy.

⚠️ COMMON MISTAKE: Students often forget to account for the initial velocity when using the work-energy theorem to find the distance covered. They also fail to consider the time taken to calculate the work done, which is essential for finding the distance traveled.

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