CBSEGrade 11MathematicsSequence and Series

Investigating Geometric Progressions?

Consider a sequence where each term is twice the previous term and starts at 4. Examine the nature of this sequence, its first three terms, and calculate the fifth term. Can you generalize the sequence and find a formula for its nth term?

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📌 CONCEPT: A geometric progression is a sequence of numbers in which each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio.

📐 RULE / FORMULA: The nth term of a geometric progression can be found using the formula: an = a1 * r^(n-1), where a1 is the first term and r is the common ratio.

💡 WORKED EXAMPLE: Consider the given sequence with a1 = 4 and r = 2. To find the fifth term, we use the formula an = a1 * r^(n-1). Substituting n = 5, a1 = 4, and r = 2, we get a5 = 4 * 2^(5-1) = 4 * 2^4 = 4 * 16 = 64.

⚠️ COMMON MISTAKE: Students often confuse the formula for the nth term of a geometric progression and incorrectly use an = a1 + r^(n-1).

05 Oct 26