Gravitational Redshift Puzzle?
A laser is emitted from the surface of a celestial body, such as a white dwarf. If this laser signal reaches Earth, its frequency would be observed to be lower than its original frequency. How would the gravitational redshift of light from this celestial body relate to its mass and radius?
1 Answer
📌 CONCEPT: The gravitational redshift of light from a celestial body is related to its mass and radius, causing the frequency of emitted light to decrease as it escapes from the body due to the strong gravitational field.
📐 RULE / FORMULA: According to the theory of general relativity, the gravitational redshift is given by the formula: β = (1 - μ) / μ, where β is the redshift and μ is the gravitational potential at the surface of the celestial body.
💡 WORKED EXAMPLE: Consider a white dwarf with mass M and radius R. If the gravitational potential at its surface is μ = M ∙ R / (4 ∙ π ∙ c ²), then the redshift of light emitted from its surface would be β = (1 - M · R / (4 · π · c ²)) / (M · R / (4 · π · c ²)).
⚠️ COMMON MISTAKE: Students often confuse the gravitational redshift with the Doppler shift, which is a change in frequency due to the relative motion of the source and observer. The gravitational redshift is a consequence of the strong gravitational field of the celestial body, not just the relative motion of the source and observer.
12 Sept 26
🔗 More from Chapter 7: Gravitation
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