Complex Roots of Quadratic Equations?
Consider the quadratic equation x^2 + 2√3x + 4 = 0. Show that it has complex roots and find these roots. What can you infer about the nature of the roots from the coefficients of the quadratic equation?
1 Answer
📌 CONCEPT: Complex roots of a quadratic equation occur when the discriminant (b^2 - 4ac) is negative. This indicates that the quadratic equation has no real roots, and its roots are in the form of complex numbers.
📐 RULE / FORMULA: The roots of a quadratic equation ax^2 + bx + c = 0 are given by the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. The nature of the roots can be determined by the discriminant (b^2 - 4ac).
💡 WORKED EXAMPLE: For the given quadratic equation x^2 + 2√3x + 4 = 0, we can determine the nature of its roots by calculating the discriminant. The discriminant is (2√3)^2 - 4(1)(4) = 12 - 16 = -4, which is negative. Therefore, the roots are complex. Using the quadratic formula, we get x = (-2√3 ± √(-4)) / 2 = (-2√3 ± 2i) / 2. The roots are (-√3 ± i).
⚠️ COMMON MISTAKE: Students often forget to check the nature of the roots by calculating the discriminant, leading to incorrect conclusions about the roots being real or complex.
03 Sept 26
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