A Vehicle Saves Energy
A car travels 60 km/h on a highway when its engine speed is 1500 rpm. Then it enters a hilly section where it climbs a 10 m high slope. If the car's engine speed drops to 800 rpm, calculate the work done against gravity in either case and explain why the car saves energy when climbing the hill.
1 Answer
📌 CONCEPT: The work done against gravity is the energy expended to overcome the gravitational potential energy difference between the initial and final positions of the vehicle.
📐 RULE / FORMULA: Work done (W) against gravity can be calculated using the formula W = mgh, where m is the mass of the vehicle, g is the acceleration due to gravity, and h is the height through which the vehicle moves.
💡 WORKED EXAMPLE: If a car weighs 1500 kg and climbs a 10 m high slope, calculate the work done against gravity. Given g = 9.8 m/s^2, W = 1500 * 9.8 * 10 = 147000 J. Now, if the car's engine speed drops to 800 rpm, the work done remains the same as the mass and height remain unchanged.
⚠️ COMMON MISTAKE: Students often forget to consider the change in potential energy when the car's engine speed changes, leading to incorrect work done calculations.
05 Jul 26
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