A Vehicle Pushed Up a Hill?
A car is being pushed up a 10° incline with a force of 200 N parallel to the slope. If the car's mass is 500 kg and it is moving at a constant speed, determine the force of friction opposing the motion.
1 Answer
📌 CONCEPT: When an object is moving at a constant speed up an inclined surface, the force of friction opposing the motion is equal to the component of the applied force that is parallel to the surface.
📐 RULE / FORMULA: F_f = F_p × sin(ξ), where F_f is the force of friction, F_p is the applied force (200 N in this case), and ξ is the angle of the incline (10°).
💡 WORKED EXAMPLE: To find the force of friction, we can substitute the values into the formula: F_f = 200 N × sin(10°) = 200 N × 0.1736 = 34.72 N.
⚠️ COMMON MISTAKE: Students often forget to use the correct angle in the formula, or they calculate the force of friction without considering the component of the applied force parallel to the surface.
11 Sept 26
🔗 More from Chapter 4: Laws of Motion
Practice this chapter
Get AI-generated board exam questions, track your mastery, and identify weak spots.
Start Free →