A Person Climbing a Rope?
A person of mass 60 kg climbs a rope with a speed of 1 m/s. Assuming the rope is inextensible, the tension in the rope is 500 N. The angle between the rope and the horizontal is 60°. What is the force exerted by the person on the rope?
1 Answer
📌 CONCEPT: The force exerted by the person on the rope is the tension in the rope, which is equal to the weight of the person plus the force required to move the person up the rope at a constant speed. This force is directed at an angle to the horizontal, and we can resolve it into its horizontal and vertical components. The force exerted by the person on the rope is equal to the tension in the rope, which is the force required to move the person up the rope at a constant speed.
📐 RULE / FORMULA: We can use the equation F = T, where F is the force exerted by the person on the rope, and T is the tension in the rope. The tension in the rope is given by T = mg + Fv, where m is the mass of the person, g is the acceleration due to gravity, and Fv is the force required to move the person up the rope at a constant speed.
💡 WORKED EXAMPLE: Let's consider the given situation. The mass of the person is 60 kg, the speed is 1 m/s, the tension in the rope is 500 N, and the angle between the rope and the horizontal is 60°. We can resolve the tension into its horizontal and vertical components: Fv = T sin(60°) = 500 sin(60°) = 433 N. Since the person is moving at a constant speed, the force required to move the person up the rope is equal to the force exerted by the person on the rope, which is 433 N.
⚠️ COMMON MISTAKE: Students often forget to resolve the tension into its horizontal and vertical components, or they incorrectly apply the equation F = T, without considering the force required to move the person up the rope at a constant speed.
30 Sept 26
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