A Car's Braking System - Efficiency and Safety?
A car is moving at a speed of 50 m/s when the driver suddenly applies the brakes. The car's mass is 1500 kg. If the brakes are applied uniformly over a distance of 20 m, will the car come to a complete stop? If not, what would be the remaining speed of the car and how does it relate to the coefficient of kinetic friction between the car's tires and the road?
1 Answer
📌 CONCEPT: The efficiency and safety of a car's braking system depend on the force of friction between the car's tires and the road, which can be calculated using the coefficient of kinetic friction and the normal force exerted by the car on the road.
📐 RULE / FORMULA: The force of kinetic friction (F) is given by the formula F = μk × N, where μk is the coefficient of kinetic friction and N is the normal force (which is equal to the car's weight, mg).
💡 WORKED EXAMPLE: Suppose the car's mass is 1500 kg and the coefficient of kinetic friction is 0.3. If the car is moving at a speed of 50 m/s when the brakes are applied, and the brakes are applied uniformly over a distance of 20 m, we can calculate the force of friction and determine if the car will come to a complete stop.
⚠️ COMMON MISTAKE: Students often mistake the coefficient of kinetic friction for the coefficient of static friction, which is a different value. Additionally, they may forget to consider the normal force when calculating the force of friction.
03 Aug 26
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